Before start the spice simulation, can be useful have a look at what is a RLC resonator. Some of the more important equation are:
$$f_0 = \frac{1}{2\pi\sqrt{LC}};\qquad \Delta f = f_2 - f_1; \qquad Q=\frac{f_0}{\Delta f}.$$
Where $f_0$ is the resonance frequency, $f_2$ and $f_1$, the two frequencies where the impedance of the resonator is half of the maximum, or even $-3\,dB$ in the decibel graph.
If we use these component values: $R=2.2\,k\Omega$, $C=220\,nF$ and $L=100\,\mu H$, the above equations should lead to:
$$f_0 = 33.9\,kH;\qquad Q=103.18; \qquad \Delta f = 328\,Hz$$
Let's begin the spice simulation!
The description of the circuit is trivial, there are just four elementary devices, but the important things are within the control statement:
$$f_0 = \frac{1}{2\pi\sqrt{LC}};\qquad \Delta f = f_2 - f_1; \qquad Q=\frac{f_0}{\Delta f}.$$
Where $f_0$ is the resonance frequency, $f_2$ and $f_1$, the two frequencies where the impedance of the resonator is half of the maximum, or even $-3\,dB$ in the decibel graph.
If we use these component values: $R=2.2\,k\Omega$, $C=220\,nF$ and $L=100\,\mu H$, the above equations should lead to:
$$f_0 = 33.9\,kH;\qquad Q=103.18; \qquad \Delta f = 328\,Hz$$
Let's begin the spice simulation!
The description of the circuit is trivial, there are just four elementary devices, but the important things are within the control statement:
* RLC Resonator
Iin 0 n1 DC 0 AC 1
R n1 0 2.2k
L n1 0 100u
C n1 0 220n
.control
ac lin 1000 30k 40k
let Zn=v(n1)/2.2k
meas ac f_res max_at Zn
meas ac BW TRIG Zn val=0.5 RISE=1
+ TARG Zn val=0.5 FALL=1
+ TARG Zn val=0.5 FALL=1
let Q=f_res/BW
echo "The quality factor of this RLS resonator is $&Q"
write sig_plot.raw db(Zn) ph(Zn)
quit
.endc
As always to execute the script and have a log.txt file:
ngspice RLC_resonator.sp -o log.txt
Once done the ac simulation, it's defined Zn, that is the impedance of the resonator normalized with the resistance of the circuit. After that are measured the three parameters:
- $f_{res}$ or $f_0$, that is the central frequency where the response has its maximum,
- $\Delta f$, the bandwidth of the resonator, calculated between the point where Zn is half of its maximum, that in such case is one because it is normalized),
- $Q$, the quality factor of the resonator.
And that's it! Comparing the simulation results and the results given by the equations, can be noticed that are very close!
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